1/8^(-2x-6)=1/32^(-x+11)

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Solution for 1/8^(-2x-6)=1/32^(-x+11) equation: 



1/8^(-2x-6)=1/32^(-x+11)

We move all terms to the left:

1/8^(-2x-6)-(1/32^(-x+11))=0



Domain of the equation: 8^(-2x-6)!=0

x∈R





Domain of the equation: 32^(-x+11))!=0

x∈R



We add all the numbers together, and all the variables

1/8^(-2x-6)-(1/32^(-1x+11))=0

We calculate fractions


(32x(-)/(8^(-2x-6)*32^(-1x+11)))+(-8x0/(8^(-2x-6)*32^(-1x+11)))=0



We calculate terms in parentheses: +(32x(-)/(8^(-2x-6)*32^(-1x+11))), so:

32x(-)/(8^(-2x-6)*32^(-1x+11))

We add all the numbers together, and all the variables

32x0/(8^(-2x-6)*32^(-1x+11))

We multiply all the terms by the denominator


32x0

We add all the numbers together, and all the variables

32x

Back to the equation:

+(32x)





We calculate terms in parentheses: +(-8x0/(8^(-2x-6)*32^(-1x+11))), so:

-8x0/(8^(-2x-6)*32^(-1x+11))

We multiply all the terms by the denominator


-8x0

We add all the numbers together, and all the variables

-8x

Back to the equation:

+(-8x)



We get rid of parentheses

32x-8x=0

We add all the numbers together, and all the variables

24x=0

x=0/24

x=0

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